51.4k views
1 vote
What is the rate of change and initial value of the linear function modeled by a line passing through the points (0,8) and (3,-1)?

User Jazkat
by
8.5k points

1 Answer

2 votes
The rate of change is equal to rise over run
= (-1 - 8)÷(3 - 0)
= -9 ÷ 3
= -3

When you say initial value I'm assuming you mean the y-intercept

In that case you first need to find the equation of the line by substituting the gradient and point into the gradient intercept formula

y - 8 = -3(x - 0)
y = -3x + 8

The y-intercept is when x = 0 so,

y = -3(0) + 8
Therefore y = 8
User Jirkamat
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories