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What concentration of so32– is in equilibrium with ag2so3(s and 3.40 × 10-3 m ag ? the ksp of ag2so3 can be found here?

User Rijinrv
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1 Answer

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To determine the concentration of the sulfate ion in equilibrium, we can use the ICE table.

Ag2SO3 = 2Ag+ + SO3^2-
I - 0 0
C - 2x^2 x
-------------------------------------------
E - 3.40 × 10-3 x

2x^2 = 3.40×10-3
x = 0.0412 M = [SO3^2-]

Hope this answers the question. Have a nice day
User Essi
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