Question

Two pellets, each with a charge of 1 microcoulomb (10-6 c, are located 6 cm apart. (a what is the electric force between them?

Answer 1

Given two charges,
`Q_(1)` and
`Q_(2)`, we can calculate for the electric force with


`Force = \frac {k Q_(1) Q_(2)}{r^(2)}`

with k as the Coloumb constant and r as the distance given to be 3 cm or 0.03 m. Plugging this in, we have


`F = ((9.0 x 10^(9))(10^(-6))(10^(-6)))/(0.03^(2))`

Thus, we have F = 10 N.

Answer: 10N