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If the length of the centrifuge arm is 12.0 m , at what speed is the rider moving when she experiences 10 g's?

User Juanker
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The rider experienced a centripetal acceleration of 10 g's. Given that we have gravity approximated as 9.8 m/s², then 10G = 10(9.8) = 98 m/s².

Recall that centripetal acceleration can be expressed in terms of distance and v. We have


a_(centripetal) = (v^(2))/(r)

or re-arranging the equation,

v = \sqrt{(a_(centripetal))(r)} \\ v = √(98(12))\\ v = 34.3 m/s.

Answer: 34.3 m/s

User Ahocevar
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