What is the kinetic energy of a 1200 kg object that is moving at a speed of 24 m/s?

asked Jul 5, 2018 16.6k views

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7 votes

Answer:

Kinetic Energy = 1/2mv^2

m= 1200kg

v= 24 m/s

KE = 1/2 (1200kg)(24m/s)^2 = 345,600 N

Step-by-step explanation:

Hope this helps :)

Sergejs answered Jul 7, 2018

8.4k points

6 votes

Kinetic Energy = 1/2mv^2
m= 1200kg
v= 24 m/s

KE = 1/2 (1200kg)(24m/s)^2 = 345,600 N

YAnTar answered Jul 12, 2018

7.7k points

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