Question

A 50.00 ml sample of potassium hydroxide is titrated with a 0.8186 M HCl solution. The titration requires 27.87 ml of the HCl solution to reach the equivalence point. What is the molarity of the KOH solution

Answer 1

For titration procedures, it is important to determine the chemical reaction involved. For this problem, the reaction would be:

KOH + HCl = KCl + H2O

We calculate as follows:

.02787 L ( 0.8186 M ) ( 1 mol KOH / 1 mol HCl ) = 0.0228 mol KOH

MOlarity = 0.0228 / 0.05 = 0.46 M KOH