Question

Jason and Maria are playing a board game in which three dice are tossed to determine a player's move. Find each probability for: P (two 5s) , P (three 5s) , and P (one 5 or two 5s).

please show work :)

Answer 1

Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.

P(three 5s) = (1 x 1 x 1)/216 = 1/216

P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36