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A regular heptagon has sides measuring 26mm and is divided into 7 congruent triangles. Each triangle has a height of 27mm. What is the area of the heptagon?
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A regular heptagon has sides measuring 26mm and is divided into 7 congruent triangles. Each triangle has a height of 27mm. What is the area of the heptagon?

User Dmitry Krivolap
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1 Answer

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The area of any regular polygon when a side length is know is just:

A(s,n)=ns^2/(4tan(180/n)) in this case:

A(26, 7)=(7*26^2)/(4tan(180/7))

A(26, 7)=2456.5 mm^2 to nearest tenth of a mm^2
User Pavel Polivka
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