Answer:
Part 1)
![W=100-L](https://img.qammunity.org/2022/formulas/mathematics/high-school/fgc8rtv7nct95kcw3y7ysd22zm2aqh3o16.png)
Part 2)
![A(L)=L(100-L)](https://img.qammunity.org/2022/formulas/mathematics/high-school/knarunmpgf6l0zvcgsbjl39647kf3b7zw4.png)
Step-by-step
explanation:
We are given a rectangle with a perimeter of 200 feet.
Part 1)
The formula for perimeter for a rectangle is:
![200=2(L+W)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ie5pb3bhg18p525l622an1mblvkgzpl7jw.png)
We can divide both sides by 2:
![100=L+W](https://img.qammunity.org/2022/formulas/mathematics/high-school/oa1g5cinq7tpcx7r7o39sw3eszzunfkdyw.png)
And subtracting L from both sides yields:
![W=100-L](https://img.qammunity.org/2022/formulas/mathematics/high-school/fgc8rtv7nct95kcw3y7ysd22zm2aqh3o16.png)
Part 2)
The area of a rectangle is given by:
![A(L)=LW](https://img.qammunity.org/2022/formulas/mathematics/high-school/ghp4pp2mtoaa5n2mkz8h93gehofvhbpynk.png)
Since we solved for W earlier:
![A(L)=L(100-L)](https://img.qammunity.org/2022/formulas/mathematics/high-school/knarunmpgf6l0zvcgsbjl39647kf3b7zw4.png)