We need to find the probability of getting 3 tens and 2 kings
First we find possible combinations of selecting 5 cards from 52 cards
That is 52C5
We use formula n!/ r!(n-r)!
52!/ 5!(52-5)! = 2598960
In 52 cards, we have 4 tens and 4 kings
We need to select 3 tens from 4 tens
So we find 4C3 = 4!/ 3!(4-3)! = 4
We need to select 2 kings from 4 kings
So we find 4C2 = 4!/ 2!(4-2)! = 6
The probability of 3 tens and 2 queens = (4C3 * 4C2) / 52C5
(4*6)/ 2598960 = 1/108290