224k views
2 votes
Solve x3 = 64 over 27.

User Jeannot
by
6.9k points

2 Answers

5 votes
x3=64
x=21,3
.....................
User Joeann
by
7.3k points
4 votes
assuming yo meant

x^3= (64)/(27)
reemmeber

\sqrt{ (x)/(y) } = ( √(x) )/( √(y) )

so

x^3= (64)/(27)
cube root both sides

x= \sqrt[3]{ (64)/(27)}

x= \frac{ \sqrt[3]{64} }{ \sqrt[3]{27} }

x= (4)/(3)
User Nyks
by
6.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.