2.0k views
2 votes
What is the center and radius of the following circle: x^2 + (y – 6)^2 = 50

User Kathick
by
8.2k points

2 Answers

1 vote
Center: (0, 6)

radius = sqrt(50) = 5sqrt(2)
User Jeremy Lewi
by
8.9k points
1 vote


What is the center and radius of the following circle: x^2 + (y _ 6)^2 = 50,
circle quation formula is (x-a)^2 + (y-b)^2 = R², so by identifying each term, we find (x-a)^2=x^2 = (x-0)^2, (y-b)^2= (y _ 6)^2, R² = 50, implies R =5sqrt(2),
it is easy to identify that the center is (a,b)= (0, 6)
the radius is R =5sqrt(2),
User Intuitivepixel
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories