Question

in a canoe race, a team paddles downstream 480 m in 60 s. The same team makes the trip upstream in 80 s. Find the team's rate in still water and the rate of the current

Answer 1

480=60(v+s)

480=60v+60s

8=v+s

s=8-v...

480=80(v-s) using s from above we get:

480=80(v-(8-v))

6=v-8+v

6=2v-8

2v=14

v=7, and since s=8-v, s=1

So the rate of the team is 7m/s while the rate of the stream is 1m/s