Question

The solution set for 7q2 − 28 = 0 is
(Separate the solutions with a comma)

Answer 1

Solution set for the equation is {2, (-2)}.

Explanation:

The given equation is 7q² - 28 = 0

Now we add 28 on both the sides of the equation.

7q² - 28 + 28 = 0 + 28

7q² = 28

divide the equation by 7,

`(7q^(2) )/(7)=(28)/(7)`

`q^(2)=4`

`\sqrt{q^(2)}` = ±
`√(4)`

q = ± 2

Or q = 2, (-2)

Solution set for the equation is {2, (-2)}.

Answer 2

7q^2 − 28 = 0
7q^2 = 28
q^2 = 28/7
q^2 = 4
q^2= 2^2
q=+ 2 and q = -2
hope that helps