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Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has coordinates of (3, –5), which point lies on a side of the pre-image, square RSTU?

A.(–5, –3)
B.(3, –3)
C.(–1, –6)
D.(4, –9)???????????????

Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T-example-1
User DenEwout
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1 Answer

7 votes

Step 1

Find the rule of the translation of the pre-image to the image

we know that

the point S has coordinates of (
(3,-5)

the point S' has coordinates of (
(-4,1)

so

a) the rule of the translation of the pre-image to the image is


(x,y)------> (x-7,y+6)

Step 2

Find the rule of the translation of the image to the pre-image

a) the inverse rule of the translation of the image to the pre-image is


(x',y')------> (x'+7,y'-6)

Step 3

Find the coordinates of the vertices of the pre-image

Applying the inverse rule of the translation of the image to the pre-image

a) Point
R'(-8,1)


R(-8+7,1-6)=R(-1,-5)

b) Point
T'(-4,-3)


T(-4+7,-3-6)=T(3,-9)

c) Point
U'(-8,-3)


U(-8+7,-3-6)=U(-1,-9)

Step 4

Using a graphing tool

graph the points of the pre-image and the points A,B,C and D to determine the solution of the problem

we have


R(-1,-5) \\S(3,-5)\\T(3,-9)\\U(-1,-9)\\ \\A(-5,-3)\\B(3,-3)\\C(-1,-6)\\D(4,-9)

see the attached figure

therefore

the answer is the option


C(-1,-6)


Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T-example-1
User Coachcal
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8.3k points