Question

What is the force experienced by a positive test charge of 6.4 × 10-6 coulombs if the electric field strength is 2.8 × 105 newtons/coulomb?

Answer 1

For Plato students it's whatever one had 1.7 times ten to either the -2 or -3

Answer 2

Answer : F = 1.792 N

Explanation :

It is given that,

Magnitude of test charge,
`q=6.4* 10^(-6)\ C`

Electric field strength,
`E=2.8* 10^5\ N/C`

We know that the electric field is defined as the force acting per unit electric charge.

`E=(F)/(q)`

`F=qE`

`F=6.4* 10^(-6)\ C* 2.8* 10^5\ N/C`

`F=1.792\ N`

Hence, this is the required solution.