Question

Johnny uses a wheelbarrow to move planting soil to a delivery truck. The volume of planting soil that fits in the wheelbarrow measures 2 feet by 3feet by 1.5 feet. The delivery truck measures 11 feet by 8 feet and is 6 feet tall. Johnny puts soil in the delivery truck until its 70% full. What is the minimum number of times johnny needs to use the wheelbarrow until the truck is 70% full?

Answer 1

find the volume of both the wheelbarrow and truck
V=W*L*H
2*3*1.5= 9 wheelbarrow
11*8*6=528 truck
find the amount of 70% of the truck so
528*.7=369.6
369.6/9= 41.06 times

Answer 2

41 times.

Explanation:

We have,

A delivery truck measures 11 feet by 8 feet and is 6 feet tall.

⇒ Volume of the truck = 11 × 8 × 6 = 528 ft³,

Now, the volume of planting soil that fits in the wheelbarrow measures 2 feet by 3 feet by 1.5 feet.

⇒ Volume of planting soil = 2 × 3 × 1.5 = 9 ft³,

Let n be the number of times johnny needs to use the wheelbarrow until the truck is 70% full,

⇒ Volume of planting soil × n = 70 % of the volume of the truck

`\implies 9 * n = 70\% * 528`

`\implies 9n=(70* 528)/(100)`

`n = (36960)/(900)=41.0667\approx 41`

Hence, the minimum number of times johnny needs to use the wheelbarrow until the truck is 70% full is 41.