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Find a value of k such that kx^2 + 12x − 4 = 0 has one real-number solution. Explain.

User Sanil
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1 Answer

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For one and only 1 real solution, the discriminant = 0 (see chart attached)
So we know b^2-4ac=0 when the equation is in the format of ax^2+bx-c=0. Make sure your equation is in the right format first!

Given kx^2+12x-4=0
b=12
so b^2-4ac=0
144 = 4ac
144 = 4(k)(-4)
144/(-16) = k
k = -9
User Trudi
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