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I don't see how a 4 digit code can be formed given that the antiderivative is a cubic. Can anyone give me insight?

Ignore the scribble, please.

I don't see how a 4 digit code can be formed given that the antiderivative is a cubic-example-1
User PgmFreek
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1 Answer

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I believe what this question is saying (albeit poorly) is that you have 4 possible ways to encode what happens on a given interval between critical points, and not that the sequence you would submit as an answer consists of 4 digits.

For a basic example, let's consider
f(x)=x^3. We have


f'(x)=3x^2

so that
x=0 is the only critical point, and


f''(x)=6x

so that
x=0 is the only inflection point.


f'(x)>0 for all
x, while
f''(x)<0 for
x<0, and vice versa.

We have two intervals to work with,
(-\infty,0) and
(0,\infty). So in this case, the answer would be 2 over
(-\infty,0) and 1 over
(0,\infty).

That's a guess at any rate. Also, I don't know how helpful this is 4 days after the fact...
User JGNI
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