Solve the following system using the elimination method: 2a+2b=4 and 4a-3b=8

asked Mar 2, 2018 169k views

2 votes

8.0k points

Please log in or register to add a comment.

1 vote

2a+2b=4 a=1 and b=1

4a-3b=8 a=5 and b=4

hope i helped ya

7.3k points

3 votes

a = 2
b = 0

2a + 2b = 4 → 4a + 4b = 8

(4a + 4b = 8) - (4a - 3b = 8) → 7b = 0

b = 0

so a = 2

7.7k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.7m questions

11.3m answers