Question

How do i completely factor 9c^4-36c^2?

Answer 1

You would do
(3c^2+6c)(3c^2-6c)
since 3c^2 squared becomes 9c^4
and 6c times negative 6c becomes -36c^2

I just checked over and it would become
3c^2+6c[3c(c-2)]

Answer 2

You take out the biggest factor of 9 and 36 which is 9c^2. The factors both have the c variable in common so you take the least exponent and put it with the gcf.

9c^2(c^2+4)