Question

If 3x2 – x + 9 = 0, what are the values of x?

Answer 1

There are no real roots to this equation.
Mathematically speaking,if the usage of imaginary numbers are not involved,there will be no solutions to x.
You can tell by using discriminant,b^2-4ac
If discrimination is less than zero,there are no real roots to the equation.

Answer 2

`x=(1+i√(107) )/(6)`

`x=(1-i√(107) )/(6)`

Explanation:

`3x^2 - x + 9 = 0`

To solve for x we use quadratic formula

`x=(-b+-√(b^2-4ac) )/(2a)`

The value of a=3, b=-1 and c=9

Plug in the values in the formula and solve for x

`x=(-b+-√(b^2-4ac) )/(2a)`

`x=(1+-√((-1)^2-4(3)(9)) )/(2(3))`

`x=(1+-√(-107) )/(6)`

The value of square root (-1) is 'i'

`x=(1+i√(107) )/(6)`

`x=(1-i√(107) )/(6)`