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What is the 6th term of the geometric sequence where a1=1024 and a4=-16

User Oscar LT
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2 Answers

5 votes
We have to solve for the common ratio first...

The rule for a geometric sequences is:

a(n)=ar^(n-1) and we are given two terms so we can say:

-16/1024=(ar^3)/(ar^0)

-16/1024=r^3

r=(-1/64)^(1/3)

r=-1/4 so

a(n)=1024(-1/4)^(n-1)

a(6)=1024(-1/4)^5

a(6)=-1
User Sarthak Srivastava
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2 votes
a1=1,024
a2=-256
a3=64
a4=-16
a5=4
a6=-1
User Zoon Nooz
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8.7k points