Question

Which expression is equivalent to b^m•b^n

A. b^m-n
B. b^m•n
C. b^m÷n
D. b^m+n

Answer 1

`\displaystyle\\ \bold{b^m * b^n = b^(m + n)~~~(D)}\\\\ \bold{(b^m)/(b^n)= b^(m - n)~~~~~~~~~(A)}\\\\ \bold{\Big(b^m \Big)^n = b^(m* n)~~~~(B)}\\\\ \bold{\sqrt[\bold{n}]{\bold{b^m}} = b^(m/ n ) ~~~~~~(C)}`