Question

The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s.

What is the centripetal acceleration of the disc edge in m/s^2

Answer 1

By definition, centripetal acceleration is given by:

`image`

Where,

v: tangential disk speed

r: disk radius

Substituting values in the given equation we have:

`image`

Rounding the result we have:

`a = 83.8 (m)/(s^2)`

Answer:

The centripetal acceleration of the disc edge in m/s^2 is:

`a = 83.8 (m)/(s^2)`