Question

Use the Law of Sines to solve (if possible) the triangle. If two solutions exist, find both. Round your answers to two decimal places.

A = 119 degrees, a = 128, b = 106

Answer 1

(sin119)/128=sinB/106

sinB=106(sin119)/128

B=arcsin(106(sin119)/128)

B≈46.41°

C≈(180-119-46.41)=14.59°

(sin119)/128=(sin14.59)/c

c=128(sin14.59)/sin119

c≈36.87

So the sides a,b,c are 128, 106, 36.87 respectively and

angles a,b,c are 119°, 46.41°, 14.69° respectively.