Question

PLEASE HELP, I know I already asked this but this time it is 50 points

c=ax-bx
Joseph claims that if a, b, and c are non-negative integers, then the equation has exactly one solution for x. Select ALL cases that show Joseph's claim is INCORRECT.

A. A-b=1,c=0
B. A=b,c≠0
C. A=b,c=0
D. A-B=1,c≠1
E. A≠b, c=0

Answer 1

the right answers are: option 2, option 3, option 4 and option 5.

Answer 2

Expression: c = ax - bx
Take x as a common factor,
c = x(a - b)

when a=b, & c≠0 then equation won't balance, means claim is incorrect in this situation.
Again, If a≠b then equation won't balance, means claim is incorrect.

In short, Your Answer would be: Option B & E

Hope this helps!