209k views
4 votes
Fill in the blank. a surveyor measures the angle of elevation to a point on a mountain to be 18. the point on the mountain is horizontally 4 miles away from the surveyor. the vertical change in elevation from the point where the surveyor is standing to the point on the mountain is _____ miles. (round your answer to the nearest hundredth of a mile.)

2 Answers

1 vote
Use the tangent ratio here: tan(18) = x / 4...4 tan(18) = x, and x = 1.30
User Marek Dulowski
by
5.7k points
2 votes

Answer:

Using tangent ratio:


\tan \theta= \frac{\text{Opposite side}}{\text{Adjacent  side}}

As per the statement:

a surveyor measures the angle of elevation to a point on a mountain to be 18.


\theta = 18^(\circ)

It is also given that the point on the mountain is horizontally 4 miles away from the surveyor.

⇒Adjacent side = 4 miles

You can see the diagram as shown below:

Using tangent ratio we have;


\tan 18^(\circ)= \frac{\text{Opposite side}}{4}

Multiply both sides by 4 we have;


\text{Opposite side} = 4 \cdot \tan 18^(\circ)

then;


\text{Opposite side} = 4 \cdot 0.32491969623

Simplify:


\text{Opposite side} = 1.29967878

Therefore, the vertical change in elevation from the point where the surveyor is standing to the point on the mountain to the nearest hundredths is 1.30 miles

Fill in the blank. a surveyor measures the angle of elevation to a point on a mountain-example-1
User Ghostoy
by
6.0k points