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15 grams of hydrogen and 7.5 grams of oxygen were placed in a beaker. An explosion happened

inside the baker that produced water. The beaker was never opened. How many grams of water
were produced

15 grams of hydrogen and 7.5 grams of oxygen were placed in a beaker. An explosion-example-1

1 Answer

4 votes

Answer:

25.33 grams of water are produced.

Step-by-step explanation:

15 g H / 1.00784* = 14.8833 moles H

7.5 g O / 15.999** = 0.468779 moles O

Ratio of Hydrogen to Oxygen in Water: 2 : 1

Oxygen: 0.468779 moles

Hydrogen (calculated based on oxygen): 0.468779 * 2 = 0.937558 moles

Water: 0.468779 + 0.937558 = 1.406337 moles

Grams of water produced:

1.406337 mol * (water molar mass)

= 1.406337 mol * [2(1.00784) + 1(15.999)]

= 1.406337 mol * (18.01468***)

= 25.3347110272 g water

Notes:

*molar mass of hydrogen

**molar mass of oxygen

***molar mass of water is actually 18.01528, so the calculation of 18.01468 is close enough

-------------------------------- Summary --------------------------------

Convert hydrogen and oxygen to moles.

Determine number of moles of water using: 2 mole hydrogen + 1 mole oxygen = 1 mole water

Convert water moles to grams.

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