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The equation for a circle with center (h, k) is (x - h)2 (y - k)2 = r2. if a circle is modeled by the equation (x - 4)2 (y 6)2 = 49, what is the center of the circle?

The equation for a circle with center (h, k) is (x - h)2 (y - k)2 = r2. if a circle is modeled by the equation (x - 4)2 (y 6)2 = 49, what is the center of the circle?
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The equation for a circle with center (h, k) is (x - h)2 (y - k)2 = r2. if a circle is modeled by the equation (x - 4)2 (y 6)2 = 49, what is the center of the circle?

User Vineeth Kanaparthi
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8.6k points

1 Answer

2 votes
by putting the equation in standard form the center is (4,6) and the radius is 7.
User Dixkin
by
7.9k points
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