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The equation for a circle with center (h, k) is (x - h)2 (y - k)2 = r2. if a circle is modeled by the equation (x - 4)2 (y 6)2 = 49, what is the center of the circle?
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The equation for a circle with center (h, k) is (x - h)2 (y - k)2 = r2. if a circle is modeled by the equation (x - 4)2 (y 6)2 = 49, what is the center of the circle?
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Mar 21, 2018
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The equation for a circle with center (h, k) is (x - h)2 (y - k)2 = r2. if a circle is modeled by the equation (x - 4)2 (y 6)2 = 49, what is the center of the circle?
Mathematics
high-school
Vineeth Kanaparthi
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Vineeth Kanaparthi
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by putting the equation in standard form the center is (4,6) and the radius is 7.
Dixkin
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Mar 26, 2018
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Dixkin
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