32.8k views
2 votes
The equation h(t)=−16t2+70t+40 gives the height of a toy rocket, in feet, t seconds after it is launched from a platform.

What is the height of the platform?

Enter your answer in the box.

_____ ft

User Zeokav
by
9.0k points

2 Answers

3 votes
h(t)=−16t2+70t+40 gives the height of a toy rocket
height of the platform is equal to h(t) when t = 0
h(0) = 40 feet
User Neizan
by
8.6k points
6 votes

Answer:

The height of the platform is 40 ft

Explanation:

Given the equation:


h(t) = -16t^2+70t+40 ....[1]

where

h(t) gives the height of a toy rocket in feet and

t is the time in sec after it is launched from a platform.

At platform:

t = 0

We have to find the height of the platform;

Substitute t=0 in [1] we have;


h(0) = -16(0)^2+70(0)+40

Simplify:


h(0) = 40 ft

therefore, the height of the platform is 40 ft

User Lada
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories