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How many atoms are in 80.45 g of magnesium?
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How many atoms are in 80.45 g of magnesium?

User ITake
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Answer:

⬇️

There are 1.9926 * 10 ^24 atoms.


M ( Mg ) = 80.45 g

We can find the molar mass of magnesium in the Periodic table:M ( Mg ) = 24.31 g / molen = 80.45 g :

24.31 g/mole = 3.31 molesN a ( Avogadro`s constant ) = 6.02 * 10 ^23N = Na * n = 6.02 * 10 ^24 * 3.31 = 19.926 * 10 ^24

User Joe Atzberger
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