Question

In a rhombus MPKN with an obtuse angle K the diagonals intersect each other at point E. The measure of one of the angles of a ∆PKE is equal 16°. Find the measures of all angles of ∆PKE and ΔPMN. Please help!

Answer 1

m∠KEP = 90°

m∠EKP = 74°

m∠EPK = 16°

m∠N PM= 16°

m∠MNP = 16

m∠M = 148°

Explanation:

If you do RSM those are the answers

Answer 2

Angles PMN and MPN are also 16 because the triangles are isosceles.
The measure of the third angle (angle N) is 148 which also equal to the measure of angle K. The measure of angle PKE is 74 which half of the measure of angle N and angle K.