Question

How many moles of HNO3 are needed to prepare 0.9 liters of a 0.89 M solution of HNO3?

Answer 1

0.801 moles

Step-by-step explanation

The formula for calculating mole is given by

`\text{mole = Concentration (M) }*\text{ Volume (L)}`

Concentration (M) = 0.89 M

Volume (V) = 0.9 L

`\begin{gathered} \Rightarrow Mole\text{ = 0.89}*0.9 \\ Mole=0.801\text{ moles} \end{gathered}`

Therefore, 0.801 moles of HNO3 are needed to prepare 0.9 liters of a 0.89 M solution of HNO3.