Question

Find the range of values of k at which graphs of y= |(x+1)(x-3)| and y=x+k have 2 common points

Answer 1

y=x+k subtitud into y=|(x+1)(x-3)| then get x+k=(x+1)(x-3) ,next k=x^2-2x-x-3,get k=x^2-3x-3 .ankswer is x=3.79andx=-0.79