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How many solutions does sin^-1 0 have in the interval [0, pi)?

a. Infinite
b. 1
c. 2
d. 0

User Alxx
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1 Answer

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hello:
sin²(x)-1=0
sin²(x) =1
sin(x) = 1 or sin(x) = -1
in : [ 0, π ] : sin(x) ≥ 0
x= π/2.... (answer : b. 1)
User Maymay
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