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16 votes
16 votes
If logax=16; the value of loga rootsquarex is?

User Shemeemsha R A
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1 Answer

22 votes
22 votes

Given -

log (x) = 16

To Find -

Value of log(√x) =?

Step-by-Step Explanation -

log (x) = 16

Now, log(√x) can be written as:


\begin{gathered} \log_(√(x))\text{ = }\log_(x)^{(1)/(2)} \\ \\ =\text{ }(1)/(2)* log(x) \\ \\ Now,\text{ we know log x = 16} \\ \\ =\text{ }(1)/(2)*16 \\ \\ =\text{ 8} \end{gathered}

Final Answer -

Value of log(√x) = 8

User Praetor
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