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Factor completely 2x3y4 − 8x2y3 + 6xy2
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Factor completely 2x3y4 − 8x2y3 + 6xy2
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Dec 8, 2018
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Factor completely 2x3y4 − 8x2y3 + 6xy2
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Tobiasg
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Did you mean: 2x^3y^4-8x^2y^3+6xy^2?
If so the answer is:
2xy^2(xy-3)(xy-1)
BasilTomato
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Dec 15, 2018
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