Question

Use the Law of Sines to find the length of FE to the nearest tenth of a foot.

Answer 1

`(FE)/(\sin(D)) = (FD)/(\sin(E))`


`(FE)/(\sin(39^(\circ))) = (7)/(\sin(34^(\circ)))`


`FE = \sin(39^(\circ))*(7)/(\sin(34^(\circ)))`


`FE \approx 7.87785880329812`


`FE \approx 7.9`

Final Answer: 7.9 feet