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Sereja · Answer 1 · 2023-08-31T13:35:39+0000

Solution:

Given:

where;

$\begin{gathered} l=20ft \\ h=16ft \end{gathered}$

A right triangle can be extracted from the image above,

Applying the Pythagoras theorem to the right triangle,

$\begin{gathered} \text{hypotenuse}^2=\text{opposite}^2+\text{adjacent}^2 \\ \\ \text{Thus,} \\ l^2=h^2+w^2 \end{gathered}$

To find w, substitute the known values into the formula,

$\begin{gathered} l^2=h^2+w^2 \\ 20^2=16^2+w^2 \\ 400=256+w^2 \\ 400-256=w^2 \\ 144=w^2 \\ w=\sqrt[]{144} \\ w=\pm12 \\ Si\text{nce the problem is on the distance to hold the base of the ladder, we pick the positive value only.} \\ \text{Thus,} \\ w=12ft \end{gathered}$

Therefore, the distance from the wall that the base of the ladder should be while they climb back in is 12 feet.

Hence, option D is the correct answer.

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