First, we need to determine the number of coins.
10+16+17+12 =55
Notice that she replaces the coin after each draw so the number of coins does not change.
(a) What is the probability that Marissa obtains a quarter on the first draw?
P(quarter) = number of quarters/ total number of coins = 10/55 = 2/11
b) What is the probability that Marissa obtains a penny or a dime on the second draw?
P(penny or dime) = (number of pennies or dimes) / total = (12+17)/55 = 29/55
(c) What is the probability that Marissa obtains at most 10 cents worth of money on the third draw?
At most 10 cents means she can have a penny, a nickel or a dime
P(penny, nickel, or dime) = ((number of pennies, nickels or dimes)/ total = ( 16+17+12) /total = 45/55 = 9/11
(d) What is the probability that Marissa does not get a nickel on the fourth draw?
She can have a quarter, a dime or a penny, ( no nickels)
P( no nickel) = (number of quarters, dimes or pennies) /total = ( 10+17+12)/ total = 39/55
(e) What is the probability that Marissa obtains at least 10 cents worth of money on the fifth draw?
She must get at least 10 cents, which is a dime or a quarter
P(dime or quarter) = (number of dimes or quarters) / total = (10+17)/55 = 27/55