Question

A rope of 2/5 length meters is cut into 4 equal cords

Answer 1

To solve the exercise you only have to divide the length of the rope by 4

`((2)/(5))/(4)`

Which is equivalent to

`((2)/(5))/((4)/(1))=(2)/(5)/(4)/(1)`

By definition of the fractional division you have

`(a)/(b)/(c)/(d)=(a)/(b)\cdot(d)/(c)=(a\cdot d)/(b\cdot c)`

So,

`(2)/(5)/(4)/(1)=(2)/(5)\cdot(1)/(4)=(2)/(20)`

Simplifying

`(2)/(20)=(2\cdot1)/(2\cdot10)=(1)/(10)`

Therefore, the length of each cord is 1/10 meters.

Drawing a picture of the situation you have