Register
A bag contains 15 green, 18 yellow, and 16 orange balls. One ball is randomly selected. To the nearest percent, what is the probability of the event?
73.3k views
0 votes
A bag contains 15 green, 18 yellow, and 16 orange balls. One ball is randomly selected.

To the nearest percent, what is the probability of the event?

User Zstew
by
8.1k points

1 Answer

4 votes
15+18+16=49 This is your total number of balls.
You have 15/49 green balls. Plug this fraction into a calculator: 15÷49. You get 0.306 To make this a percentage, multiply it by 100. You get 30.6 which rounds up to 31%. The probability of taking out a green ball is 31%. You can find the probability of the other colors by repeating the process. Message me if you have more questions.
User JustWork
by
8.0k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Link Copied!