Question

Two frictionless blocks, having masses of 8.0 kg and 1.0 kg, rest on a horizontal surface. if a force applied to the 8.0 kg block gives it an acceleration of 5.0m/s2, then the same force will give the 1.0 kg block an acceleration (in m/s2 of

Answer 1

F = 8 (kg) 5 (m/s2) = 40N

40 = 2 (kg) a --> a = 40/2 = 20 m/s2

second part, same thing, but now a = 9.8m/s2. Gravity pulls on the book and the table pushes back with that same force.

Answer 2

Acceleration in 1 kg block = a2 = 40 m/s^2

Step-by-step explanation:

Mass of first block = m1 = 8 kg

Mass of second block = m2 = 1 kg

Acceleration in first block = a1 = 5 m/s

According to newton’s second law of motion,

F1 = m1a1 …….. (i)

As the same force is applied on second block so,

F1 = m2a2 ……… (ii)

Comparing equation (i) and (ii) ,

m1a1 = m2a2

a2 = m1a1/m2

a2 = (8)(5)/1

a2 = 40 m/s^2