Question

ABC is translated left 3 units to form the image ∆A′B′C′.

What are the coordinates of the vertices of ∆A′B′C′ ?

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Answer 1

The coordinates of triangle A'B'C' are A'(-5,-1) B'(-1,-1) C'(-1,2)

Explanation:

Translations

Given a point A(x,y), translating A by h units to the left will map it to A'(x-h,y).

The triangle ABC has coordinates: A(-2,-1) B(2,-1) C(2,2). Then translating the triangle left by h=3 units, the points are:

A'(-2-3,-1) B'(2-3,-1) C'(2-3,2)

A'(-5,-1) B'(-1,-1) C'(-1,2)

The coordinates of triangle A'B'C' are A'(-5,-1) B'(-1,-1) C'(-1,2)