Question

Write the equation of a line, in slope-intercept form, with a y-intercept at the origin and a slope of 2.Oy=x+2OY=2OY=2xO2y =x

Answer 1

y=2x

Step-by-step explanation

the equaiton of a line in slope-intercept form is given by:

`\begin{gathered} y=mx+b \\ where\text{ m is the slope and} \\ b\text{ is the y-intercept} \end{gathered}`

The y-intercept is the point where the graph intersects the y-axis, the y-coordinate of that point is b

so

Step 1

a)let

`slope=2`
`\begin{gathered} y-intercept\Rightarrow(0,0) \\ so \\ b=0 \end{gathered}`

b) now ,replace in the equation

`\begin{gathered} y=mx+b \\ y=2x+0 \\ y=2x \end{gathered}`

therefore, the equation of the line

y=2x

I hope this helps you