Question

Which of the following are solutions to the equation sinx cosx= square root 3/4 check all that apply

Answer 1

radian form, x = pi/6 and pi/3

Answer 2

Important to note: sin2x = 2sinxcosx

Since we know that property, we can divide both sides by 2 to yield: sin2x/2 = sinxcosx

So, sin2x/2 = sqrt(3)/4
sin2x = 2sqrt(3)/4 = sqrt(3)/2

2x = arcsin (sqrt(3)/2) = 60, 120 in the domain [0, 360]

x = 30, 60