Question

Y = (15-2x)^2(x+3) Can you guys help me with this one? All I know is the I can use the zero product Property on the x-intercepts

and y = x(2x+5)(2x-7)

Please actually

Answer 1

`\bf y = x(2x+5)(2x-7)\impliedby \textit{setting y = 0} \\\\\\ 0=x(2x+5)(2x-7)\implies \begin{cases} 0=x\\ ----------\\ 0=2x+5\\ -5=2x\\ \cfrac{-5}{2}=x\\ ----------\\ 0=2x-7\\ 7=2x\\ \cfrac{7}{2}=x \end{cases}`