Question

The bull's eye on an archery target has a radius of 3 inches. The entire target has a radius of 9 inches. To the nearest 10th, find the area of the target outside the bull's eye.

Answer 1

`226.1\ in^(2)`

Explanation:

we know that

The area of the target outside the bull's eye is equal to the area of the entire target minus the area of the bull's eye

so

`A=\pi (9^(2)-3^(2) )=72\pi=72(3.14)=226.1\ in^(2)`