using a quadratic regression calculator
Please wait a minute to calculate the model
we have
Pt=A+Bt+Ct^2
A=-21.90
B=14.52
C=-0.17
therefore
Part a
Pt=-0.17t^2+14.52t-21.90
Part b
Based on this model, what distance is expected for a ball hit at 55 degrees? Round your answer to the nearest tenth of a foot
For t=55 degrees
Pt=-0.17(55)^2+14.52(55)-21.90
Pt=262.5 ft
Part c
What distance is expected for a ball hit at 75 degrees? Round your answer to the nearest tenth of a foot
For t=75 degrees
Pt=-0.17(75)^2+14.52(75)-21.90
Pt=110.9 ft
Part d
Which of the two previous predictions is likely to be more reliable?
the answer is 55 degrees
Part e
What is the smallest angle that you expect to yield a distance of 200 feet? Round your answer to the nearest tenth of a degree
we have
For Pt=200 ft
200=-0.17t^2+14.52t-21.90
-0.17t^2+14.52t-221.90=0
solve the quadratic equation
the solutions are
t=19.9 degrees and t=65.5 degrees
the smallest angle is 19.9 degrees